9645 of the area under the normal distribution curve to the left of it. Your answer should be a z-score of 1.805 that has. Since you are asked to round to 3 decimal places, then your answer would be 1.805 either way. In fact, they are the same when rounded to 4 decimal places. Regardless, both methods will get you an answer that is perfectly acceptable. The reason is that the interpolation is a straight line interpolation, whereas the calculator is looking at the actual curve itself between the two z-scores, which is not a straight line. The normal distribution is the most important and most widely used distribution in statistics. That's not exactly equal to 1.805477458, but it's pretty close. If you were to use the z-score normal distribution tables, you would do the following: We then subtract the left-tail probability from the right-tail probability to get the two-tail probability, which is 0.9332. We look up -1.5 and 1.5 in the standard normal distribution table and find their respective probabilities to be 0.0668. NORM.S.DIST(z,cumulative) The NORM.S.DIST function syntax has the following arguments: Z Required. Use this function in place of a table of standard normal curve areas. I used the ti-84 plus calculator to get the more detailed answer. Say we want to find the probability of getting a z-score between -1.5 and 1.5. Returns the standard normal distribution (has a mean of zero and a standard deviation of one). This can be seen visually as shown below: 9645 of the area under the normal distribution curve to the left of it would be z = 1.805477458. values of variables occur at a regular interval. You can put this solution on YOUR website! deviation to predict future returns, but the standard deviation assumes a normal distribution.
0 Comments
Leave a Reply. |
AuthorWrite something about yourself. No need to be fancy, just an overview. ArchivesCategories |